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std.fmt: Fix incorrect behavior with large floating point integers.
I consider this an interim workaround/hack until #1299 is finished. There is a bug in the original C implementation of the errol3 (and errol4) algorithm that can result in undefined behavior or an obviously incorrect result (leading ':' in the output) This change checks for those two problems and uses a slower fallback path if they occur. I can't guarantee that this will always produce the correct result, but since the workaround is only used if the original algorithm is guaranteed to fail, it should never turn a previously-correct result into an incorrect one. Fixes #11283
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@ -2299,6 +2299,8 @@ test "float.decimal" {
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try expectFmt("f64: 0.00000", "f64: {d:.5}", .{@as(f64, 1.40130e-45)});
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try expectFmt("f64: 0.00000", "f64: {d:.5}", .{@as(f64, 9.999960e-40)});
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try expectFmt("f64: 10000000000000.00", "f64: {d:.2}", .{@as(f64, 9999999999999.999)});
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try expectFmt("f64: 10000000000000000000000000000000000000", "f64: {d}", .{@as(f64, 1e37)});
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try expectFmt("f64: 100000000000000000000000000000000000000", "f64: {d}", .{@as(f64, 1e38)});
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}
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test "float.libc.sanity" {
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@ -106,7 +106,10 @@ fn errol3u(val: f64, buffer: []u8) FloatDecimal {
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} else if (val >= 16.0 and val < 9.007199254740992e15) {
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return errolFixed(val, buffer);
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}
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return errolSlow(val, buffer);
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}
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fn errolSlow(val: f64, buffer: []u8) FloatDecimal {
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// normalize the midpoint
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const e = math.frexp(val).exponent;
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@ -336,7 +339,9 @@ fn errolInt(val: f64, buffer: []u8) FloatDecimal {
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var buf_index = u64toa(m64, buffer) - 1;
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if (mi != 0) {
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buffer[buf_index - 1] += @boolToInt(buffer[buf_index] >= '5');
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const round_up = buffer[buf_index] >= '5';
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if (buf_index == 0 or (round_up and buffer[buf_index - 1] == '9')) return errolSlow(val, buffer);
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buffer[buf_index - 1] += @boolToInt(round_up);
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} else {
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buf_index += 1;
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}
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