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Fix rendering of type names

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This commit is contained in:
Martin Wickham 2021-09-30 15:40:11 -05:00
parent 269e548770
commit b1e5081826
1 changed files with 7 additions and 4 deletions
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11
src/Module.zig
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@ -617,12 +617,15 @@ pub const Decl = struct {
return tree.tokens.items(.start)[decl.srcToken()];
}
pub fn renderFullyQualifiedName(decl: Decl, writer: anytype) !void {
const unqualified_name = mem.spanZ(decl.name);
return decl.namespace.renderFullyQualifiedName(unqualified_name, writer);
pub fn renderFullyQualifiedName(decl: *const Decl, writer: anytype) @TypeOf(writer).Error!void {
// Namespace decls (struct/enum/union/opaque) use their own namespace,
// which means the decl name and the namespace name are the same.
// In that case we want to omit the decl name, unless this is the root decl.
const unqualified_name = if (decl.namespace.getDecl() != decl or decl.namespace.parent == null) mem.spanZ(decl.name) else "";
return try decl.namespace.renderFullyQualifiedName(unqualified_name, writer);
}
pub fn getFullyQualifiedName(decl: Decl, gpa: *Allocator) ![:0]u8 {
pub fn getFullyQualifiedName(decl: *const Decl, gpa: *Allocator) ![:0]u8 {
var buffer = std.ArrayList(u8).init(gpa);
defer buffer.deinit();
try decl.renderFullyQualifiedName(buffer.writer());