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typeName: amend return type to string literal

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This was already the case, but the documentation failed to point out
that the returned value is of type `*const [N:0]u8`, i.e. that of a
string literal.

Also adds a behavioral test to assert that this is the case.
This commit is contained in:
Daniele Cocca 2021-04-28 01:13:47 +01:00 committed by Daniele Cocca
parent 171102ea7c
commit 9be2f76741
2 changed files with 11 additions and 1 deletions
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2
doc/langref.html.in
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@ -8623,7 +8623,7 @@ test "integer truncation" {
{#header_close#}
{#header_open|@typeName#}
<pre>{#syntax#}@typeName(T: type) [N]u8{#endsyntax#}</pre>
<pre>{#syntax#}@typeName(T: type) *const [N:0]u8{#endsyntax#}</pre>
<p>
This function returns the string representation of a type, as
an array. It is equivalent to a string literal of the type name.

10
test/behavior/bugs/3779.zig
View File

@ -19,3 +19,13 @@ test "@errorName() returns a string literal" {
try std.testing.expectEqualStrings("TestErrorCode", error_name);
try std.testing.expectEqualStrings("TestErrorCode", ptr_error_name[0..error_name.len]);
}
const TestType = struct {};
const type_name = @typeName(TestType);
const ptr_type_name: [*:0]const u8 = type_name;
test "@typeName() returns a string literal" {
try std.testing.expectEqual(*const [type_name.len:0]u8, @TypeOf(type_name));
try std.testing.expectEqualStrings("TestType", type_name);
try std.testing.expectEqualStrings("TestType", ptr_type_name[0..type_name.len]);
}