std.Build.CompileStep: better default step name

This commit is contained in:
Andrew Kelley 2023-02-28 21:13:54 -07:00
parent 7da34bd9e8
commit 7efeedcd89

View File

@ -312,6 +312,12 @@ pub fn create(builder: *std.Build, options: Options) *CompileStep {
panic("invalid name: '{s}'. It looks like a file path, but it is supposed to be the library or application name.", .{name});
}
const step_name = builder.fmt("compile {s} {s} {s}", .{
name,
@tagName(options.optimize),
options.target.zigTriple(builder.allocator) catch @panic("OOM"),
});
const self = builder.allocator.create(CompileStep) catch @panic("OOM");
self.* = CompileStep{
.strip = null,
@ -328,7 +334,7 @@ pub fn create(builder: *std.Build, options: Options) *CompileStep {
.frameworks = StringHashMap(FrameworkLinkInfo).init(builder.allocator),
.step = Step.init(builder.allocator, .{
.id = base_id,
.name = name,
.name = step_name,
.makeFn = make,
}),
.version = options.version,