std.debug: lock stderr mutex when panicking

The doc comments for this global said:
"Locked to avoid interleaving panic messages from multiple threads."

Huh? There's already a mutex for that, it's the stderr mutex. Lock that
one instead.
This commit is contained in:
Andrew Kelley 2024-06-11 15:14:06 -07:00
parent 0cef727e59
commit 55a9ea250c

View File

@ -447,9 +447,6 @@ pub fn panicExtra(
/// The counter is incremented/decremented atomically.
var panicking = std.atomic.Value(u8).init(0);
// Locked to avoid interleaving panic messages from multiple threads.
var panic_mutex = std.Thread.Mutex{};
/// Counts how many times the panic handler is invoked by this thread.
/// This is used to catch and handle panics triggered by the panic handler.
threadlocal var panic_stage: usize = 0;
@ -474,8 +471,8 @@ pub fn panicImpl(trace: ?*const std.builtin.StackTrace, first_trace_addr: ?usize
// Make sure to release the mutex when done
{
panic_mutex.lock();
defer panic_mutex.unlock();
lockStdErr();
defer unlockStdErr();
const stderr = io.getStdErr().writer();
if (builtin.single_threaded) {
@ -2604,8 +2601,8 @@ fn handleSegfaultPosix(sig: i32, info: *const posix.siginfo_t, ctx_ptr: ?*anyopa
_ = panicking.fetchAdd(1, .seq_cst);
{
panic_mutex.lock();
defer panic_mutex.unlock();
lockStdErr();
defer unlockStdErr();
dumpSegfaultInfoPosix(sig, code, addr, ctx_ptr);
}
@ -2680,8 +2677,8 @@ fn handleSegfaultWindowsExtra(
_ = panicking.fetchAdd(1, .seq_cst);
{
panic_mutex.lock();
defer panic_mutex.unlock();
lockStdErr();
defer unlockStdErr();
dumpSegfaultInfoWindows(info, msg, label);
}